Is (−2,2) a viable solution for the following system? Explain. −7x+2y=18 3x+3y=0 (1 point) Responses (−2,2) is a viable solution since it makes both equations true. left parenthesis negative 2 comma 2 right parenthesis is a viable solution since it makes both equations true. (−2,2) is a viable solution since it makes one equation true. left parenthesis negative 2 comma 2 right parenthesis is a viable solution since it makes one equation true. (−2,2) is a nonviable solution since it makes one equation true. left parenthesis negative 2 comma 2 right parenthesis is a nonviable solution since it makes one equation true. (−2,2) is a nonviable solution since it makes neither equation true.

Answer 1

To determine whether the point \((-2, 2)\) is a viable solution for the system of equations, we need to substitute \(x = -2\) and \(y = 2\) into each equation and check if both equations are satisfied.

1. For the first equation:
   \(-7x + 2y = 18\)
   Substituting \(x = -2\) and \(y = 2\):
   \(-7(-2) + 2(2) = 14 + 4 = 18\)
   This equation is satisfied.

2. For the second equation:
   \(3x + 3y = 0\)
   Substituting \(x = -2\) and \(y = 2\):
   \(3(-2) + 3(2) = -6 + 6 = 0\)
   This equation is also satisfied.

Since \((-2, 2)\) makes both equations true, it is a viable solution.

Thus, the correct response is:
\((-2,2)\) is a viable solution since it makes both equations true.