We can substitute the values x=1 and y=1 into the inequalities to check if it satisfies both:
4(1) + 15(1) ≥ 19
1 + 1 < 2
Simplifying the first inequality, we have:
4 + 15 ≥ 19
19 ≥ 19
This is true.
Simplifying the second inequality, we have:
1 + 1 < 2
This is also true.
Therefore, the point (1, 1) satisfies both inequalities and is a solution to the system.
Is (1, 1) a solution to this system of inequalities?
4x + 15y ≥ 19
x + y < 2
1 answer