This is quite simple. The coefficients tell you what is going on. The equation tells you that 4 mols Fe react with 3 mols O2 to produce 2 mols Fe2O3.
So the ratio of Fe used (4 mols) to iron(III) oxide produced(2 mols) is 4:2. right. In other words, mols Fe2O3 produced is just 1/2 that of Fe used.
Iron(III) oxide is formed when iron combines with oxygen in the air. What is the mole ration of Fe used and the mole of Iron(iii) oxide produced? 4Fe(s) + 3O2(g) > 2Fe2O3(s)
a - 3:2
b - 4:3
c - 4:2
d - 3:4
Can someone help?
1 answer