The volume of the rectangular block of iron can be calculated using the formula V = l × w × h, where l, w, and h are the length, width, and height of the block, respectively.
V = 3.000 cm × 4.000 cm × 5.000 cm = 60.000 cm³
The mass of the block is equal to the volume multiplied by the density, M = ρ × V, where ρ is the density of iron.
M = 7.874 g/cm³ × 60.000 cm³ = 472.44 g
Therefore, the mass of the rectangular block of iron is 472.44 g.
Iron has a density of 7.874 g/cm3. What is the mass of a rectangular block of iron with dimensions of 3.000 cm by 4.000 cm by 5.000 cm?
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