Z = (score-mean)/SD
2.33 = (x-100)/15
Solve for x.
IQ test scores are normally distributed with a mean of 100 and a standard deviation of 15. Find the x- score that corresponds to a z-score of 2.33.
4 answers
143.2
134.95
x=mean+score * SD
x=100+2.33*15=134.95
so x=134.95
x=100+2.33*15=134.95
so x=134.95