k = 0.693/t1/2
ln(No/N) = kt
No = 10.0g
N = unknown
k from above
t = 56
Another way to solve this:
10/2n
56 days is 7 half lives so
10/27 = ?
Iodine-131, a beta emitter, has a half-life of 8 days.How many grams of a 10.0g sample of iodine-131 would remain after 56.0 days?
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2 answers