In a circle, if we have a right triangle inscribed where one side is the diameter (AB), it follows that the angle opposite that diameter (∠ACB) must be 90 degrees due to the inscribed angle theorem.
Since arc BC is given as 62 degrees, we can find the angle ∠ABC using the property that the measure of an inscribed angle is half the measure of the arc it intercepts.
Here, arc BC is intercepting angle ∠ABC. Therefore, we calculate:
\[ \angle ABC = \frac{1}{2} \times \text{measure of arc BC} = \frac{1}{2} \times 62^\circ = 31^\circ \]
Thus, ∠ABC measures 31 degrees.
The correct answer is: \(\angle ABC\) is 31 degrees.