intergrate 3x-4/x^2-4x+4

Answer 1

I assume you mean
(3x-4)dx/(x-2)^2

3x dx/(x-2)^2 - 4 dx/(x-2)^2

3[ -2/(x-2) + ln(x-2) ] -4 [ -1/(x-2) ]

-6/(x-2) + 3 ln(x-2) + 4/(x-2)

-2/(x-2) + 3 ln(x-2)