intergral of (x^3 -4x + 3)/(2x) dx
would this be ln abs(x^3-4x+3) + C?
I don't really understand how to solve this problem.
d/dx (tan (x^2))
sec^2(x^2)(2x)
would this be the correct answer to find the derivative of tan (x^2)?
no, because if you differentiate your answer you don't get what you started with.
divide the 2x into each term so that your expression becomes
(1/2)x^2 - 2 + 3/(2x)
now the integral of that is
(1/6)x^3 + 2x + (3/2)lnx + c
yes, to your derivative of tan x^2