interge[1/(t*t-1)(t*t-1)]

Question

I haven't got a way to solve it.. please help me..

Answer 1

If you mean

∫ 1/(t^2-1)^2 dt

try using partial fractions:

1/(t^2-1)^2 =

1/4 (1/(t+1) + 1/(t+1)^2 - 1/(t-1) + 1/(t-1)^2)

each of those is easy to integrate.