I=∫ xsinxcosx dx (subst. double angle)
=(1/2)∫ xsin(2x) dx
Integrate by parts
I=-(1/4)xcos(2x)+(1/4)∫ cos(2x) dx
=-(1/4)xcos(2x)+(1/8)sin(2x)+C
Integrate ∫ xsinxcosx dx
2 answers
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2 answers