Integrate ( x^2cosx)/(1+sinx)^2 dx

with limits from 0 to pi/4

2 answers

Wolfram gives us this
http://integrals.wolfram.com/index.jsp?expr=%28+x%5E2cosx%29%2F%281%2Bsinx%29%5E2&random=false

I have no clue how they got that.
but i want step by step