Ask a New Question
Search
Integrate x^2/(sqrt(x^2-25)dx
1 answer
let
x = 5 secθ
dx = 5 secθ tanθ
√(x^2-25) = 5 tanθ
x^2 = 25 sec^2θ
Things will get much simpler.
Ask a New Question
or
answer this question
.
Similar Questions
Please do help solve the followings
1) Integrate e^4 dx 2) Integrate dx/sqrt(90^2-4x^2) 3) Integrate (e^x+x)^2(e^x+1) dx 4)
0 answers
Integrate: 1/(x-sqrt(x+2) dx
I came up with: (2/3)(2*ln((sqrt(x+2))-2)+ln((sqrt(x+2))-1)) but it keeps coming back the wrong
0 answers
Calc length of arc of y=ln(x) from x=1 to x=2
---- So far: Definite Integral over x=(1,2) of sqrt(1 + 1/x) dx 1/x = tan^2 t x =
1 answer
Question: ∫(x^2)/sqrt(x^2+1)
u=x^2+1 , x^2= u-1, du=2xdx ∫(u-1)/sqrt(u) , expand ∫u/sqrt(u) - 1/sqrt(u) Integrate:
1 answer
more similar questions