Integrate using the simplest method possible:

∫(t – 1)5(2t – 7)dt

2 answers

For me, the easiest method is to multiply everything together which will give you a sum of terms. From there you can integrate.
I think that the 5 is an exponent

∫(t – 1)^5(2t – 7)dt

expanding is still an option, but if we let u = t-1 then we have

2t-7 = 2u-5 and we have

∫u^5(2u-5)du

Now expansion is a sight less work