Integrate: (The Sq. Root Of x-2)/x+1 dx Let u= (Sq. Root Of x-2)

Answer 1

Possibly this might give you some ideas:

dx (x-2)^.5/(x+1)
u = (x-2)^.5
du = (1/2)(x-2)^-.5 dx
so
dx = 2(x-2)^.5 du
u^2 = x-2
so
x = u^2+2
then
du *2*u^2/(u^2+3)

from integral table:
int of dx x^2/(ax^2+c) =(x/a)-(c/a)int of dx/(ax^2+c)