Integrate the following indefinite integral:


(sin7x)^12 * (cos7x)^3

Hint: sin^2 + cos^2 = 1

2 answers

= int [(sin7x)^12 * (cos7x)^2 * cos7x *dx]
= int [(sin7x)^12 * (1-sin 7x)^2 * cos7x *dx]
=int [(sin7x)^12 * cos 7x * dx] - int [(sin7x)^12 * (sin 7x)^2 * cos7x *dx]
=int[u^12*(1/7)*du] - int[u^14*(1/7)*du]
=(1/7)*(1/13)*u^13 - (1/7)*(1/15)*u^15 + C
=(1/7)*u^13*( (1/13) - (1/15)*u^2 ) + C
=(1/7)*(sin 7x)^13 * ( (1/13) - (1/15)*(sin7x)^2 ) + C
THANK YOU SOOOOOOOOOOOOOO MUCH!~!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Similar Questions
  1. 1. Find the indefinite integral.Indefinite integral tan^3(pix/7)sec^2(pix/7)dx 2. Find the indefinite integral by making the
    1. answers icon 1 answer
  2. find all values of x on interval 0-2pi.(sin4x)(cos7x)=(cos4x)(sin7x) identities should be used.
    1. answers icon 1 answer
  3. the expression cos4x cos3x + sin4x sin3x is equivalent towhich one of the following is the answer: 1) sinx 2) sin7x 3) cosx 4)
    1. answers icon 4 answers
    1. answers icon 0 answers
more similar questions