Integrate (t√t+√t/t^2,)dx

Answer 1

To integrate the given expression, we first simplify it:

∫(t√t + √t/t^2) dx
= ∫(t^(3/2) + t^(-1/2)) dx

Now, we integrate each term separately:

= ∫t^(3/2) dx + ∫t^(-1/2) dx
= (2/5)t^(5/2) + 2t^(1/2) + C

Therefore, the final integral is:

(2/5)t^(5/2) + 2t^(1/2) + C