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Integrate sqrt(x^2 + 1) dx over [0,2*pi]

I can substitute u=arctan x to get:

Integrate (sec u)^3 du over [0,arctan(2*pi)]

From there, I'm stuck.

(thanks Count Iblis for your last help)

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nevermind, I got it. The trick was using trigonometric reduction formulas.

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