do one step of a long division to get
(x^2)/(x^2+1)
= 1 - 1/(x^2+1)
∫(x^2)/(x^2+1)dx
= ∫( 1 - 1/(x^2+1))dx
= x - tan^-1 (x) + c ,
the last part should be part of your repertoire of integrals
Integrate it in step by step applying integration by partial fraction.
∫(x^2)/(x^2+1)dx
1 answer
1 answer