integral u^3(sqrtu+u^(1/5))du from 0 to 2
=?
integral (t^3=6t^2+4)dt from 0 to x
f''(x)=?
2 answers
what's with the + sign in the integral?
∫ u^3(√u + u^(1/5)) du
= e^(7/2) + u^(16/5) du
those are just normal power problems.
∫ u^3(√u + u^(1/5)) du
= e^(7/2) + u^(16/5) du
those are just normal power problems.