integral of : x^2/y

1 answer

To find the integral of the function \( \frac{x^2}{y} \), we can treat \( y \) as a constant with respect to \( x \) if we are integrating with respect to \( x \). The integral can be expressed as:

\[ \int \frac{x^2}{y} , dx \]

Since \( \frac{1}{y} \) is a constant, we can factor it out of the integral:

\[ = \frac{1}{y} \int x^2 , dx \]

Now, we can compute the integral of \( x^2 \):

\[ \int x^2 , dx = \frac{x^3}{3} + C \]

where \( C \) is the constant of integration. Substituting this back into our expression gives us:

\[ \frac{1}{y} \left( \frac{x^3}{3} + C \right) = \frac{x^3}{3y} + \frac{C}{y} \]

So the integral of \( \frac{x^2}{y} \) with respect to \( x \) is:

\[ \int \frac{x^2}{y} , dx = \frac{x^3}{3y} + C' \]

where \( C' = \frac{C}{y} \) is a constant of integration.