integral of sin(x^2) dx

Question

i actually got the ans, but aftr differentiating the answer i am not getting back the question

Answer 1

let u=x^2
du= 2x dx

dx=du/2x
dx=du/2sqrt(u)

-1/4 cos u is the integral

Answer 2

http://www.numberempire.com/integralcalculator.php

This involves the error function, not an elementary problem. Hannah has made an error.

Answer 3

I'm sorry about that. Can you explain why there is an error Mr. Pursley? I genuinely don't understand how there is an error.

Answer 4

Your substitutions are good, but you dropped something. You should have watched the details:

∫sin(x^2) dx = ∫sin(u) / 2√u du

Answer 5

then how do we proceed ??
is their any solution to this problem?