integral of (secx)(sinx)

1 answer

To solve the integral \( \int \sec(x) \sin(x) , dx \), we can use a substitution method.

Recall that \( \sec(x) \) can be written as \( \frac{1}{\cos(x)} \). Therefore, we can rewrite the integral as:

\[ \int \sec(x) \sin(x) , dx = \int \frac{\sin(x)}{\cos(x)} , dx = \int \tan(x) , dx \]

The integral of \( \tan(x) \) is:

\[ \int \tan(x) , dx = -\ln |\cos(x)| + C \]

where \( C \) is the constant of integration.

Thus, the final answer is:

\[ \int \sec(x) \sin(x) , dx = -\ln |\cos(x)| + C \]