change in x speed = 6.5 cos50-4.2cos34.5
change in y speed = -6.5 sin50-4.2sin34.5
ax = change in x speed/2
ay = change in y speed/2
a = sqrt (ax^2+ay^2)
A = angle of a above horizontal
tan A = ay/ax
Initially, a particle is moving at 4.20m/s at an angle of 34.5∘ above the horizontal. Two seconds later, its velocity is 6.50m/s at an angle of 50.0∘ below the horizontal.
What was the particle's average acceleration during these 2.00 seconds?
1 answer