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inding vertex and focus of parabola y^2 +4y +8x - 12 =0

1 answer

y^2 + 4 y = -8 x + 12

y^2 + 4 y + 4 = -8 x + 16

(y+2)^2 = -8 (x-2)

vertex at (2,-2) opens left etc
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