m = (-5 - 1)/(2-4) = 3
m' = -1/m = -1/3
y = -x/3 + b
find point on original line halfway between
x = (4 +2 )/2 = 3
y = (1 - 5)/2 = -2
so
-2 = -3/3 + b
b = -1
so
y = -x/3 - 1
3 y = -x - 3
Indicate the equation of the line that is the perpendicular bisector of the segment with endpoints (4, 1) and (2, -5).
1 answer