indentify the vertex of y=-10(x+15)^2-18

1 answer

To find the vertex of the quadratic function given in vertex form \( y = a(x - h)^2 + k \), we can identify the vertex directly from the equation.

The function provided is:

\[ y = -10(x + 15)^2 - 18 \]

We can rewrite it to match the vertex form:

\[ y = -10(x - (-15))^2 - 18 \]

From this, we can identify:

  • \( h = -15 \)
  • \( k = -18 \)

Thus, the vertex of the parabola is \( (h, k) = (-15, -18) \).

So, the vertex is:

\[ \boxed{(-15, -18)} \]