ind two consecutive even integers such that the smaller added to five times the larger is 58

Answer 1

Let the smaller even integer be n.
The larger is then n+2.
The problem says
"smaller added to five times the larger is 58"
which translates to
n+5(n+2)=58
Solve for n (smaller even integer)

Answer 2

a = first number

b = second number

b = a + 2

a + 5 ( a + 2 ) = 58

a + 5 a + 10 = 58

6 a + 10 = 58 Subtrac 10 to both sides

6 a + 10 - 10 = 58 - 10

6 a = 48 Divide both sides by 6

6 a / 6 = 48 / 6

a = 8

b = a + 2 = 8 + 2 = 10

Your numbers are 8 and 10

8 + 5 * 10 = 8 + 50 = 58