#include <iostream.h>

#include <stdlib.h>
#include <math.h>

int main ( )
{
double noe, nod, dc1, dc2, dc3, dc4, t;
cout << "Enter number of eggs: ";
cin >> noe;
nod = noe / 12;
dc1 = .50 / 12;
dc2 = .45 / 12;
dc3 = .40 / 12;
dc4 = .35 / 12;
cout.setf(ios::fixed);
cout.precision(3);
if (nod >4) {
goto 1;
}
if ( (nod >4) && (nod <6) ) {
goto 2;
}
else
}
{
if ( (nod >6) && (nod <11) )
}
goto 3;
{
else
}
{
if (nod >11)
}
goto 4;
{
else
}
{
1:
t = noe * dc1;
cout << "Your cost is $0.50 per dozen or " << dc1 << " per egg.";
cout << endl;
goto end;
2:
t = noe * dc2;
cout << "Your cost is $0.45 per dozen or " << dc2 << " per egg.";
goto end;
3:
t = noe * dc3;
cout << "Your cost is $0.40 per dozen or " << dc3 << " per egg.";
goto end;
4:
t = noe * dc4;
cout << "Your cost is $0.35 per dozen or " << dc4 << " per egg.";
cout.setf(ios::fixed);
cout.precision(2);
cout << "Your bill comes to " << t;
cout << endl;
cout << endl;
system("Pause");
return (0);
}

9 answers

A few things to check:
The first test is true for any number greater than 4. If you enter 5, the first test will go to label 1. Maybe the first test should be less than 4.
Another item to check:
You are not including the endpoints in the range check.
From your code:
if ( (nod >4) && (nod <6) ) {
goto 2;
}
else
}
{
if ( (nod >6) && (nod <11) )
}
goto 3;
---------------
If you enter 6, it will not satisfy either of these.
i did that. it still doesn't work :*(

thanks for your help but can you try compliaing it?
Does it compile OK?
If so, what is the test input that is failing?
Looking again:
Labels cannot begin with a number.
1: is wrong
L1: would be OK
Try changing your labels ( and goto's).
Your braces are backwards after your "else"
should be:
else {
}

Your 3rd and 4th "if" statements have backward braces also.
it says it has a unidentifair berfore numberic constant
OK,
Post the code you just tried.
Also, which line is the compiler complaining about?
still doesn't work :(
how do you convert 2 for binary to decimal using c++ program
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