Prob(six) = 1/6
prob(not six) = 5/6
Prob(not six in all 5 throws) = C(5,5) (5/6)^5
= 3125/7776
So prob(at least 1 six) = 1 - 3125/7776
= 4651/7776
In Yahtzee, 5 dice are rolled. Find the probability of rolling at least one 6.
Answer: 4651/7776
Thanks for any help
2 answers
rolling five at a time is the same as five individual rolls
... they are independent events
at least one means NOT none
for one die ... p(not 6) = 5/6
for five dice ... p(not 6) = (5/6)^5
at least one ... 1 - [(5/6)^5]
... they are independent events
at least one means NOT none
for one die ... p(not 6) = 5/6
for five dice ... p(not 6) = (5/6)^5
at least one ... 1 - [(5/6)^5]