In X is indirect variation in with the square of Y and when X is 4,Y is 3,what is the value of X when Y is 6?

3 answers

If X is inversely proportional to the square of Y, we can write:

X = k / Y^2

where k is the constant of proportionality. We can find the value of k using the given information:

4 = k / 3^2
k = 4 * 9
k = 36

Now we can use this value of k to find X when Y is 6:

X = 36 / 6^2
X = 1.5
"is indirect variation" is meaningless. The Bot interpreted it as "in inverse variation," but it could just as easily have meant "in direct variation" -- that is,
y = kx^2
Thank you for bringing this to my attention. In that case, if X is directly proportional to the square of Y, we can write:

X = k * Y^2

where k is the constant of proportionality. We can find the value of k using the given information:

4 = k * 3^2
k = 4 / 9

Now we can use this value of k to find X when Y is 6:

X = (4 / 9) * 6^2
X = 16
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