Let's denote the number of boys in the school as \( b \) and the number of girls as \( g \).
According to the problem, we have two equations:
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The total number of pupils is: \[ b + g = 3000 \]
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There are 250 more girls than boys: \[ g = b + 250 \]
Now we can substitute the second equation into the first equation:
\[ b + (b + 250) = 3000 \]
This simplifies to:
\[ 2b + 250 = 3000 \]
Subtracting 250 from both sides gives us:
\[ 2b = 2750 \]
Dividing both sides by 2 gives:
\[ b = 1375 \]
Now we can find the number of girls using the second equation:
\[ g = b + 250 = 1375 + 250 = 1625 \]
The number of boys is 1375.
To find the percentage of pupils that are boys, we use the following formula:
\[ \text{Percentage of boys} = \left( \frac{b}{b+g} \right) \times 100 \]
Substituting \( b \) and the total number of pupils into the formula:
\[ \text{Percentage of boys} = \left( \frac{1375}{3000} \right) \times 100 \]
Calculating this gives:
\[ \text{Percentage of boys} = \frac{1375}{3000} \times 100 = \frac{137500}{3000} \approx 45.8333\ldots% \]
In fraction form, the percentage of boys can be expressed as:
\[ \frac{1375}{3000} = \frac{11}{24} \text{ (after simplifying)} \]
Thus, the percentage of pupils that were boys is approximately \( 45.83% \) and in simplified fraction form, it is \( \frac{11}{24} \).
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