To determine the quadrant in which the angle θ lies based on the conditions given, we need to analyze the signs of the trigonometric functions involved.
- We have \( \tan \theta = -\sqrt{3} \). The tangent function is negative in Quadrants II and IV.
- We also know that \( \sin \theta > 0 \). The sine function is positive in Quadrants I and II.
Since we need both conditions to be true (tangent negative and sine positive), θ must be in Quadrant II.
Thus, the correct answer is:
Quadrant II