Think of degrees if radians give you trouble
π radians = 180°
so (-5/6)π radians = -(5/6)(180)° = -150°
so going clockwise 150° would put you into quadrant III
In which quadrant is the terminal side of angle A?
A = -5π/6
a. Quadrant III
b. Quadrant I
c. Quadrant II
d. Quadrant IV
4 answers
Hello, i cant find out the values of x1,x2 can u help me please?
sinx=2sinx+1
0=sinx+1
sinx=-1 <0 (III;IV)
sinx=270*
x1= ?
x2= ?
sinx=2sinx+1
0=sinx+1
sinx=-1 <0 (III;IV)
sinx=270*
x1= ?
x2= ?
to Fred:
sinx=2sinx+1
0=2sinx+1-sinx
0=sinx+1
sinx=-1
We are going to look for the values of x.
sin is < 0 meaning, the values are either in quadrant III/ IV.
First, identify the rad equivalent where sin equates to -1.
And that would be 270 degrees or 3pi/2 located at the 3rd quadrant.
3rd quadrant (check!)
4th quadrant (?)
The range for the 3rd quadrant is 180-270 degrees, and the range of for 4th quadrant is from 270-360 degrees.
if you have a limit such as the values are only within [0, 2pi] then you only need 3pi/2 since its within the 3rd and 4th quadrant.
x1= 3pi/2. x2= 3pi/2.
sinx=2sinx+1
0=2sinx+1-sinx
0=sinx+1
sinx=-1
We are going to look for the values of x.
sin is < 0 meaning, the values are either in quadrant III/ IV.
First, identify the rad equivalent where sin equates to -1.
And that would be 270 degrees or 3pi/2 located at the 3rd quadrant.
3rd quadrant (check!)
4th quadrant (?)
The range for the 3rd quadrant is 180-270 degrees, and the range of for 4th quadrant is from 270-360 degrees.
if you have a limit such as the values are only within [0, 2pi] then you only need 3pi/2 since its within the 3rd and 4th quadrant.
x1= 3pi/2. x2= 3pi/2.
In which quadrant does the terminal side of a 240° angle in standard position lie?