In which of the given sets of numbers are all the numbers solutions of 18+2x≥36 ?(1 point)

Question

Responses

9, 10, 11, 12

0, 3, 9, 12

9, 8, 7, 6

8, 7, 6

Answer 1

The correct set of numbers where all the numbers are solutions of 18 + 2x ≥ 36 is:

9, 10, 11, 12

To verify:

For 9: 18 + 2(9) = 18 + 18 = 36
For 10: 18 + 2(10) = 18 + 20 = 38
For 11: 18 + 2(11) = 18 + 22 = 40
For 12: 18 + 2(12) = 18 + 24 = 42

So, all the numbers in the set 9, 10, 11, 12 are solutions of 18 + 2x ≥ 36.