In the first set (9, 10, 11, 12), all the numbers are solutions of 18 + 2x ≥ 36.
For 9: 18 + 2(9) = 18 + 18 = 36 (which satisfies the inequality)
For 10: 18 + 2(10) = 18 + 20 = 38
For 11: 18 + 2(11) = 18 + 22 = 40
For 12: 18 + 2(12) = 18 + 24 = 42
Only 9 satisfies the given inequality from the first set of numbers.
In which of the given sets of numbers are all the numbers solutions of 18 + 2x ≥ 36
9, 10, 11, 12
9, 8, 7, 6
8, 7, 6
0, 3, 9, 12
1 answer
1 answer