In which of the given sets of numbers are all the numbers solutions of 18+2x≥36 ?(1 point)

Question

Responses

0, 3, 9, 12
0, 3, 9, 12

9, 10, 11, 12
9, 10, 11, 12

9, 8, 7, 6
9, 8, 7, 6

8, 7, 6

Answer 1

In the set 9, 10, 11, 12, all the numbers are solutions of 18 + 2x ≥ 36.

Substitute each number into the inequality:
1. 18 + 2(9) ≥ 36
18 + 18 ≥ 36
36 ≥ 36 (True)

2. 18 + 2(10) ≥ 36
18 + 20 ≥ 36
38 ≥ 36 (True)

3. 18 + 2(11) ≥ 36
18 + 22 ≥ 36
40 ≥ 36 (True)

4. 18 + 2(12) ≥ 36
18 + 24 ≥ 36
42 ≥ 36 (True)

Therefore, the set 9, 10, 11, 12 only contains numbers that satisfy the given inequality.