The given equation is 4x + 7 = 23.
Let's substitute the numbers from each set into the equation and check if they satisfy it.
A. 1, 2, 3, 4:
1. 4(1) + 7 = 11 (does not equal 23)
2. 4(2) + 7 = 15 (does not equal 23)
3. 4(3) + 7 = 19 (does not equal 23)
4. 4(4) + 7 = 23 (equals 23)
Set A has one solution for the equation - 4.
B. 3, 4, 5, 6:
1. 4(3) + 7 = 19 (does not equal 23)
2. 4(4) + 7 = 23 (equals 23)
3. 4(5) + 7 = 27 (does not equal 23)
4. 4(6) + 7 = 31 (does not equal 23)
Set B has one solution for the equation - 4.
C. 2, 3, 4, 5:
1. 4(2) + 7 = 15 (does not equal 23)
2. 4(3) + 7 = 19 (does not equal 23)
3. 4(4) + 7 = 23 (equals 23)
4. 4(5) +7 = 27 (does not equal 23)
Set C has one solution for the equation - 4.
D. 4, 5, 6, 7:
1. 4(4) + 7 = 23 (equals 23)
2. 4(5) + 7 = 27 (does not equal 23)
3. 4(6) + 7 = 31 (does not equal 23)
4. 4(7) + 7 = 35 (does not equal 23)
Set D has one solution for the equation - 4.
Therefore, in all given sets of numbers, only the number 4 is a solution of the equation 4x + 7 = 23.
In which of the given sets of numbers are all the numbers solutions of 4x + 7 ‡ 23 • A. 1.2.3,4
• B. 3, 4,5,6
• C. 2.3,4.5
• D. 4,5.6,7
1 answer