In which of the given sets of numbers are all the numbers solutions of 4x+7≠23 ? (1 point)

Responses

3, 4, 6, 7
3, 4, 6, 7

4, 5, 6, 7
4, 5, 6, 7

2, 3, 5, 6
2, 3, 5, 6

1, 2, 3, 4

3 answers

In order to find the set of numbers that are all solutions of the inequality 4x+7 ≠ 23, we need to substitute each number into the inequality and check if it holds true.

Let's check each set of numbers:
1) For the set {3, 4, 6, 7}, let's substitute each number:
For 3: 4(3) + 7 = 19, which is not equal to 23
For 4: 4(4) + 7 = 23, which is equal to 23 (not a solution)
For 6: 4(6) + 7 = 31, which is not equal to 23
For 7: 4(7) + 7 = 35, which is not equal to 23
Therefore, none of the numbers in this set are solutions to the inequality.

2) For the set {4, 5, 6, 7}, let's substitute each number:
For 4: 4(4) + 7 = 23, which is equal to 23 (not a solution)
For 5: 4(5) + 7 = 27, which is not equal to 23
For 6: 4(6) + 7 = 31, which is not equal to 23
For 7: 4(7) + 7 = 35, which is not equal to 23
Therefore, none of the numbers in this set are solutions to the inequality.

3) For the set {2, 3, 5, 6}, let's substitute each number:
For 2: 4(2) + 7 = 15, which is not equal to 23
For 3: 4(3) + 7 = 19, which is not equal to 23
For 5: 4(5) + 7 = 27, which is not equal to 23
For 6: 4(6) + 7 = 31, which is not equal to 23
Therefore, none of the numbers in this set are solutions to the inequality.

4) For the set {1, 2, 3, 4}, let's substitute each number:
For 1: 4(1) + 7 = 11, which is not equal to 23
For 2: 4(2) + 7 = 15, which is not equal to 23
For 3: 4(3) + 7 = 19, which is not equal to 23
For 4: 4(4) + 7 = 23, which is equal to 23 (not a solution)
Therefore, none of the numbers in this set are solutions to the inequality.

From all the sets, we can see that none of the numbers in any of the sets are solutions to the inequality 4x+7 ≠ 23. Therefore, the answer is none of the above sets.
DO BETTER
Apologies for the mistake in the previous response. Let's reassess the sets of numbers and determine which one contains all the solutions to the inequality 4x+7≠23.

1) For the set {3, 4, 6, 7}, let's substitute each number:
For 3: 4(3) + 7 = 19, which is not equal to 23
For 4: 4(4) + 7 = 23, which is equal to 23 (not a solution)
For 6: 4(6) + 7 = 31, which is not equal to 23
For 7: 4(7) + 7 = 35, which is not equal to 23
Therefore, this set does not contain all the solutions to the inequality.

2) For the set {4, 5, 6, 7}, let's substitute each number:
For 4: 4(4) + 7 = 23, which is equal to 23 (not a solution)
For 5: 4(5) + 7 = 27, which is not equal to 23
For 6: 4(6) + 7 = 31, which is not equal to 23
For 7: 4(7) + 7 = 35, which is not equal to 23
Therefore, this set does not contain all the solutions to the inequality.

3) For the set {2, 3, 5, 6}, let's substitute each number:
For 2: 4(2) + 7 = 15, which is not equal to 23
For 3: 4(3) + 7 = 19, which is not equal to 23
For 5: 4(5) + 7 = 27, which is not equal to 23
For 6: 4(6) + 7 = 31, which is not equal to 23
Therefore, this set does not contain all the solutions to the inequality.

4) For the set {1, 2, 3, 4}, let's substitute each number:
For 1: 4(1) + 7 = 11, which is not equal to 23
For 2: 4(2) + 7 = 15, which is not equal to 23
For 3: 4(3) + 7 = 19, which is not equal to 23
For 4: 4(4) + 7 = 23, which is equal to 23 (not a solution)
Therefore, this set does not contain all the solutions to the inequality.

After reassessing all the sets, we can conclude that none of the given sets {3, 4, 6, 7}, {4, 5, 6, 7}, {2, 3, 5, 6}, {1, 2, 3, 4} contain all the solutions to the inequality 4x + 7 ≠ 23.
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