In order for a number to be a solution of 4x + 7 ≠ 23, it has to be any number except the solution to 4x + 7 = 23.
To find the solution to 4x + 7 = 23, we subtract 7 from both sides and then divide by 4:
4x + 7 - 7 = 23 - 7
4x = 16
x = 4
Therefore, we check which sets of numbers do not include 4 as a solution:
1, 2, 3, 4 - This set does include 4, so it is not a valid set.
4, 5, 6, 7 - This set does include 4, so it is not a valid set.
2, 3, 5, 6 - This set does not include 4, so it is a valid set.
3, 4, 6, 7 - This set does include 4, so it is not a valid set.
The set that includes all numbers that are solutions of 4x + 7 ≠ 23 is 2, 3, 5, 6.
In which of the given sets of numbers are all the numbers solutions of 4x+7≠23? (1 point) Responses 1, 2, 3, 4 1, 2, 3, 4 4, 5, 6, 7 4, 5, 6, 7 2, 3, 5, 6 2, 3, 5, 6 3, 4, 6, 7 3, 4, 6, 7
1 answer