The inequality 18+2x ≥ 36 can be rewritten as 2x ≥ 18.
Now, let's check each set of numbers to see if all the numbers satisfy the inequality:
- For the set of numbers 8, 7, 6, plugging in these values into the inequality gives: 2(8) = 16 < 18, 2(7) = 14 < 18, and 2(6) = 12 < 18. Therefore, this set does not satisfy the inequality.
- For the set of numbers 9, 10, 11, 12, plugging in these values gives: 2(9) = 18 ≥ 18, 2(10) = 20 ≥ 18, 2(11) = 22 ≥ 18, and 2(12) = 24 ≥ 18. Therefore, this set satisfies the inequality.
- For the set of numbers 0, 3, 9, 12, plugging in these values gives: 2(0) = 0 < 18, 2(3) = 6 < 18, 2(9) = 18 ≥ 18, and 2(12) = 24 ≥ 18. Therefore, this set satisfies the inequality.
- For the set of numbers 9, 8, 7, 6, plugging in these values gives: 2(9) = 18 ≥ 18, 2(8) = 16 < 18, 2(7) = 14 < 18, and 2(6) = 12 < 18. Therefore, this set does not satisfy the inequality.
Based on these checks, the sets of numbers that satisfy the inequality are: 9, 10, 11, 12 and 0, 3, 9, 12.
In which of the given sets of numbers are all the numbers solutions of 18+2x≥36 ?(1 point) Responses 8, 7, 6 8, 7, 6 9, 10, 11, 12 9, 10, 11, 12 0, 3, 9, 12 0, 3, 9, 12 9, 8, 7, 6
1 answer