In which chemical equation is the number of atoms in the reactants the same as the number of atoms in the products?(1 point)

Question

Responses

CH4 + O2 → CO2 + 2H2O
CH 4 + O 2 → CO 2 + 2H 2 O

Zn + 2HCl → H2 + ZnCl2
Zn + 2HCl → H 2 + ZnCl 2

Li2CO3 → LiO + CO2
Li 2 CO 3 → LiO + CO 2

CO2 + H2O → CH2OH + O2
CO 2 + H 2 O → CH 2 OH + O 2

Answer 1

To determine which chemical equation has the same number of atoms on both sides (reactants and products), we need to count the number of atoms for each element in the reactants and products.

1. CH₄ + O₂ → CO₂ + 2H₂O

   • Reactants: C(1) + H(4) + O(2) = 7 atoms
   • Products: C(1) + O(2) + H(4) = 7 atoms

2. Zn + 2HCl → H₂ + ZnCl₂

   • Reactants: Zn(1) + H(2) + Cl(2) = 5 atoms
   • Products: H(2) + Zn(1) + Cl(2) = 5 atoms

3. Li₂CO₃ → LiO + CO₂

   • Reactants: Li(2) + C(1) + O(3) = 6 atoms
   • Products: Li(1) + C(1) + O(2) = 4 atoms

4. CO₂ + H₂O → CH₂OH + O₂

   • Reactants: C(1) + O(3) + H(2) = 6 atoms
   • Products: C(1) + H(2) + O(3) = 6 atoms

After analyzing all options, we can see that both the first and second equations have the same number of atoms on both sides:

• CH₄ + O₂ → CO₂ + 2H₂O has 7 atoms on both sides.
• Zn + 2HCl → H₂ + ZnCl₂ also has 5 atoms on both sides.

Thus, both reactions have the same number of atoms in the reactants and products.