To determine which chemical equation has the same number of atoms in the reactants as in the products, we need to count the atoms on both sides of each equation.
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CH4 + O2 → CO2 + 2H2O
- Reactants: 1 C (from CH4) + 4 H (from CH4) + 2 O (from O2) = 1 C + 4 H + 2 O = 7 atoms
- Products: 1 C (from CO2) + 2 O (from CO2) + 4 H (from 2H2O) = 1 C + 4 H + 2 O = 7 atoms
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CO2 + H2O → CH2OH + O2
- Reactants: 1 C (from CO2) + 2 O (from CO2) + 2 H (from H2O) + 1 O (from H2O) = 1 C + 2 O + 2 H = 5 atoms
- Products: 1 C (from CH2OH) + 2 H (from CH2OH) + 1 O (from CH2OH) + 2 O = 1 C + 2 H + 3 O = 6 atoms
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Zn + 2HCl → H2 + ZnCl2
- Reactants: 1 Zn + 2 H (from 2HCl) + 2 Cl (from 2HCl) = 1 Zn + 2 H + 2 Cl = 5 atoms
- Products: 1 H (from H2) + 1 Zn (from ZnCl2) + 2 Cl (from ZnCl2) = 1 H + 1 Zn + 2 Cl = 4 atoms
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Li2CO3 → LiO + CO2
- Reactants: 2 Li (from Li2CO3) + 1 C (from Li2CO3) + 3 O (from Li2CO3) = 2 Li + 1 C + 3 O = 6 atoms
- Products: 1 Li (from LiO) + 1 O (from LiO) + 1 C (from CO2) + 2 O (from CO2) = 1 Li + 1 C + 3 O = 5 atoms
Based on the analysis, the equation "CH4 + O2 → CO2 + 2H2O" is the only one where the number of atoms in the reactants equals the number of atoms in the products.
Therefore, the correct answer is:
CH4 + O2 → CO2 + 2H2O