In wave A, the distance between two consecutive crests (wavelength, λ) is longer compared to wave B, which has a shorter distance between the crests. As a result, wave B has a shorter wavelength compared to wave A.
The frequency of a wave is inversely related to its wavelength (frequency = speed/wavelength). Since the wavelength in wave B is shorter, it will have a greater frequency compared to wave A.
So, compared to wave A, wave B has a shorter wavelength and greater frequency.
The correct response is:
shorter wavelength and greater frequency.