5/8 = x/(2x-10)
x = perimeter of smaller
2x - 10 = perimeter of larger
8x = 10x -50
-2x = -50 x = 25 smaller
2x-10 2(25)-10 = 50 -10 or 40 for larger
in two congruent triangles the ratio of lengths of two corresponding sides is 5:8. If the perimeter of the larger triangle is 10 ft less than twice the perimeter of the smaller triangle find the perimeter of each triangle
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