In TV picture, faint, slightly offset ghost images are formed when the signal from the transmitter travels to the receiver both directly and indirectly after reflection from a building or some other large metallic mass. In a 25 inch set, the ghost is about 1 cm to the right of the principal image if the reflected signal arrives .6 us after the principal signal. In this case, what is the difference in the distance traveled by the two signals?

Question

In TV picture, faint, slightly offset ghost images are formed when the signal from the transmitter travels to the receiver both directly and indirectly after reflection from a building or some other large metallic mass.  In a 25 inch set, the ghost is about 1 cm to the right of the principal image if the reflected signal arrives .6 us after the principal signal.  In this case, what is the difference in the distance traveled by the two signals?

ok I am totally confused on this one! please help!

Damon · Answer

time = 0.6 * 10^-6 seconds if I understand your u to be "micro" speed of electromagnetic wave = 3*10^8 m/s approximately so distance difference = 3*10^8 * 0.6*10^-6 = 1.8 * 10^2 = 180 meters

DrBob222 · Answer

distance = rate x time. distance = 3 x 10^8 m/s x 0.6 x 10^-6 sec.The way I read the problem, this is the distance traveled from the transmitter to the reflector to the receiver.