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In triangular ABC, AB =6cm BC=7cm and AC=8cm. What is the difference between the largest and the smallest angle of a triangle.

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You know that angle B is the greatest (since b is the longest side)
and angle C is the smallest, since c is the shortest side.
find A using law of cosines:
b^2 = a^2 + c^2 - 2ac cosB
Find C the same way, or using the law of sines:
sinC/c = sinB/b
Now just find B-C
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