In triangle XYZ, |XY|= 8 cm and |YZ|=6m.
The area of triangle XYZ is 12cm^2. The |<PQR|= 30 degrees, 150 degrees.
Find the two possible |XZ|
3 answers
Given XYZ, WTF is PQR?
I mean |<XYZ|
XZ^2 = 6^2 + 8^2 - 2*6*8cosY
cosY is either sqrt(3)/2 or -sqrt(3)/2
XZ^2 = 100-96*.866
XZ = 4.1
or
XZ^2 = 100+96*.866
XZ = 13.5
cosY is either sqrt(3)/2 or -sqrt(3)/2
XZ^2 = 100-96*.866
XZ = 4.1
or
XZ^2 = 100+96*.866
XZ = 13.5
1 answer