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In triangle PQR, m∠P = 53º, PQ = 7.4, and PR = 9.6. What is m∠R to the nearest degree?

(1 point)
Responses

61º
61º

49º
49º

42º
42º

35º
35º

3 answers

42º
RQ^2 = 9.6^2 + 7.4^2 - 2*9.6*7.4 cos53°
RQ = 7.84

sinR/7.4 = sin53°/7.84
R = 48.9°
48.9º
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