In triangle, L, M, N, comma△LMN, start overline, L, M, end overline, \cong, start overline, N, L, end overline

LM

NL
and m, angle, N, equals, 44, degrees, .m∠N=44

. Find m, angle, L, .m∠L.

1 answer

In triangle \( \triangle LMN \), we know that \( \overline{LM} \cong \overline{NL} \). This tells us that triangle \( \triangle LMN \) is isosceles, with the two sides \( LM \) and \( NL \) being congruent.

Given that \( m\angle N = 44^\circ \), we can denote \( m\angle L = x \) and \( m\angle M = x \) since the angles opposite the equal sides are equal.

Using the triangle sum theorem, we know that the sum of the angles in a triangle is \( 180^\circ \):

\[ m\angle L + m\angle M + m\angle N = 180^\circ \]

Substituting the known values:

\[ x + x + 44^\circ = 180^\circ \]

This simplifies to:

\[ 2x + 44^\circ = 180^\circ \]

Next, we can subtract \( 44^\circ \) from both sides:

\[ 2x = 180^\circ - 44^\circ \] \[ 2x = 136^\circ \]

Now, divide both sides by 2:

\[ x = \frac{136^\circ}{2} = 68^\circ \]

Thus, we find:

\[ m\angle L = 68^\circ \]

Therefore, the measure of angle \( L \) is

\[ \boxed{68^\circ} \]